Mobile App development with PhoneGap

[Original Post from my blog OnlyMS.Net]

I am now starting to get into mobile app development and to start mobile app development using a suitable tool, I choose PhoneGap. I choose PhoneGap because to develop mobile app using PhoneGap I do not need to learn anything new as I know HTML, JavaScript, CSS and these things are using here to develop any mobile app for iOS, Android, Windows, Blackberry, Bada etc mobile OS.

To start PhoneGap first install node.js from here.
Next go to command line in your windows and type following (link here)

C:\> npm install -g phonegap

It will start installing the software.


Read full learning from here and can read basic stuff from  here.

Send File from Server to Client using C# Socket Programming 5/6

ß Previous part

Full codes are here...

Client code:

using System;

using System.Collections.Generic;

using System.Text;

using System.Net;

using System.Net.Sockets;

using System.IO;

namespace Client_Socket

{

//FILE TRANSFER USING C#.NET SOCKET - CLIENT

class Program

{

static void Main(string[] args)

{

try

{

Console.WriteLine("That program can transfer small file. I've test up to 850kb file");

IPAddress[] ipAddress = Dns.GetHostAddresses("localhost");

IPEndPoint ipEnd = new IPEndPoint(ipAddress[0], 5656);

Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);

clientSock.Connect(ipEnd);

byte[] clientData = new byte[1024 * 5000];

string receivedPath = "C:/";

int receivedBytesLen = clientSock.Receive(clientData);

int fileNameLen = BitConverter.ToInt32(clientData, 0);

string fileName = Encoding.ASCII.GetString(clientData, 4, fileNameLen);

Console.WriteLine("Client:{0} connected & File {1} started received.", clientSock.RemoteEndPoint, fileName);

BinaryWriter bWrite = new BinaryWriter(File.Open(receivedPath + fileName, FileMode.Append)); ;

bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);

Console.WriteLine("File: {0} received & saved at path: {1}", fileName, receivedPath);

bWrite.Close();

clientSock.Close();

Console.ReadLine();

}

catch (Exception ex)

{

Console.WriteLine("File Sending fail." + ex.Message);

}

}

}

}

Next part (Server Code) à

Send File from Server to Client using C# Socket Programming 4/6

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6) Client Action: This section of code is retrieving file name length and by using this file name which was sent by server at the starting of file data. This will require retrieving file name.

int fileNameLen = BitConverter.ToInt32(clientData, 0);

string fileName = Encoding.ASCII.GetString(clientData, 4, fileNameLen);

7) Client Action: Now received data is saving at client side by using below lines of code with the help of binary stream writer.

BinaryWriter bWrite = new BinaryWriter(File.Open(receivedPath + fileName, FileMode.Append));

bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);

Here file data is starting to retrieve after file size and file name bytes. This has managed in 2^nd line.

By that way one small file can be sent from server to client.

8) Client and Server Action: Now server and client both will do same activity; that is to release server and client socket by using close method of socket. Client needs to close binary stream writer as well.

So by following these steps a file can be sent from server to client. Same way we can send large file from server to client. TCP buffer can not handle large data size at a time. So if you try to send large file it will throw overflow error. To avoid this error you need to slice big file in small pieces (same thing has applied in 2GB file transfer article) and need to send one by one slice. So there will be loop to send file from server to client that means step 5 to step 7 will repeat.

Also server can send some particular file based on client request. But for that client need to send file name at the time of server request. So server can search file based on this information, so can read and send particular file to client.

By handling multiple clients objects one server can send file to multiple clients simultaneously but for that you need to create multithread application and need to keep track client socket object array with data file. So programming must be more complex. I am planning to write codes up to multiple client to client large file transfer with the help of one server application step by step. So keep watching my blog to learn new things.

Download this project from below link:

https://rapidshare.com/files/691859425/Client and Server - Send Small File from Server to Client.zip  

Next part ( full codes) à

Send File from Server to Client using C# Socket Programming 3/6

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4) Server Action: These codes are not directly related with socket programming. This is using to read and send file to client.

string fileName = "test.txt";// "Your File Name";

string filePath = @"C:\FT\";//Your File Path;

byte[] fileNameByte = Encoding.ASCII.GetBytes(fileName);

byte[] fileData = File.ReadAllBytes(filePath + fileName);

byte[] clientData = new byte[4 + fileNameByte.Length + fileData.Length];

byte[] fileNameLen = BitConverter.GetBytes(fileNameByte.Length);

fileNameLen.CopyTo(clientData, 0);

fileNameByte.CopyTo(clientData, 4);

fileData.CopyTo(clientData, 4 + fileNameByte.Length);

These lines of code reading some particular file from local drive and string its data in byte array “clientData”. File data need to store in array with raw byte format to send these to client. With data file name size string at initial of file data. This is predefined between client and server and it needs to do, otherwise client will not get file name which is sending by server.

For my case I am using first four byte to represent file name length and form 5^th byte file name is storing. So all file data will store after file name.

5) Server Action: Now file data is in byte array and it needs to send to client. The same thing is happening by using below code with the help of client socket (clientSock) object, which was created during client request acceptance.

clientSock.Send(clientData);

Basically server application task ends here for small file transfer. Remaining code has used for some decoration and socket closing related things.

5) Client Action: Now again turn comes to client and it will perform below tasks:

byte[] clientData = new byte[1024 * 5000];

string receivedPath = "C:/";

int receivedBytesLen = clientSock.Receive(clientData);

Here first two lines are just creating byte array to store server data and path is used to decide where data to be save. In my code, I am saving data in C: drive.

Last line is start receiving data from server. Whenever client socket starts receiving server data then it returns length of data which has captured in a integer variable.

Next part à

Send File from Server to Client using C# Socket Programming 2/6

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2) Client Action: Now turn is coming to client to request server.

IPAddress[] ipAddress = Dns.GetHostAddresses("localhost");

IPEndPoint ipEnd = new IPEndPoint(ipAddress[0], 5656);

Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);

clientSock.Connect(ipEnd);

These codes are from client application, here first two lines are using to get Localhost IP address and by using this creating new IPEnd point. Be sure there IP address and port number must be same as server address. I am running my applications in same machine so using localhost.

Next two lines of code is creating a socket object and trying to connect by using IPEnd point. So this socket object will try to connect server socket which was in listen mode.

3) Server Action: Again turn comes to server about to response on client’s request and this is doing by below line of code in server application:

Socket clientSock = sock.Accept();

This “sock” is server socket object which was created previously and it was in listen mode. This sock object will accept client request and generate a new socket object with name “clientSock”. Rest all work in server side will be performed by “clientSock” object to handle this particular client request.

Next part à

File Transfer using C# .Net Socket Programming 2/3

Previous part ß

Phase 3, Break communication channel and release resources: When last slice of byte data saved at server, client and server close the socket object and release all resource like file stream, socket object etc.

By that way a file transferred from client to server. But there has no way to call a client from server and send file. My example describe how to send file from client to server but can you imagine how opposite done? Yes if you able learn client to server data transfer properly then it is very easy. Try your self first, if failed then try it again and continue at least three times, then you will able to do it. But….but again failed then ask me I will help you about it :-).

For code url is:

https://rapidshare.com/files/3633340435/Small_File_Transfer_in_Console.zip

Client Code:

[C#]

using System;

using System.Collections.Generic;

using System.Text;

using System.Net;

using System.Net.Sockets;

using System.IO;

namespace Client_Socket

{

//FILE TRANSFER USING C#.NET SOCKET PROGRAMMING - CLIENT

class Program

{

static void Main(string[] args)

{

try

{

Console.WriteLine("That program can transfer small file. I've test up to 850kb file");

IPAddress[] ipAddress = Dns.GetHostAddresses("localhost");

IPEndPoint ipEnd = new IPEndPoint(ipAddress[0], 5656);

Socket clientSock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);

string fileName = "Your File Name";

string filePath = "Your File Path";

byte[] fileNameByte = Encoding.ASCII.GetBytes(fileName);

byte[] fileData = File.ReadAllBytes(filePath + fileName);

byte[] clientData = new byte[4 + fileNameByte.Length + fileData.Length];

byte[] fileNameLen = BitConverter.GetBytes(fileNameByte.Length);

fileNameLen.CopyTo(clientData, 0);

fileNameByte.CopyTo(clientData, 4);

fileData.CopyTo(clientData, 4 + fileNameByte.Length);

clientSock.Connect(ipEnd);

clientSock.Send(clientData);

Console.WriteLine("File:{0} has been sent.", fileName);

clientSock.Close();

Console.ReadLine();

}

catch (Exception ex)

{

Console.WriteLine("File Sending fail." + ex.Message);

}

}

}

}
[Visual Basic]

Imports System
Imports System.Collections.Generic
Imports System.Text
Imports System.Net
Imports System.Net.Sockets
Imports System.IO
Namespace Client_Socket
'FILE TRANSFER USING C#.NET SOCKET PROGRAMMING- CLIENT
Class Program
Private Shared Sub Main(ByVal args As String())
Try
Console.WriteLine("That program can transfer small file. I've test up to 850kb file")
Dim ipAddress As IPAddress() = Dns.GetHostAddresses("localhost")
Dim ipEnd As New IPEndPoint(ipAddress(0), 5656)
Dim clientSock As New Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP)


Dim fileName As String = "Your File Name"
Dim filePath As String = "Your File Path"
Dim fileNameByte As Byte() = Encoding.ASCII.GetBytes(fileName)

Dim fileData As Byte() = File.ReadAllBytes(filePath + fileName)
Dim clientData As Byte() = New Byte(4 + fileNameByte.Length + (fileData.Length - 1)) {}
Dim fileNameLen As Byte() = BitConverter.GetBytes(fileNameByte.Length)

fileNameLen.CopyTo(clientData, 0)
fileNameByte.CopyTo(clientData, 4)
fileData.CopyTo(clientData, 4 + fileNameByte.Length)

clientSock.Connect(ipEnd)
clientSock.Send(clientData)
Console.WriteLine("File:{0} has been sent.", fileName)
clientSock.Close()
Console.ReadLine()
Catch ex As Exception
Console.WriteLine("File Sending fail." & ex.Message)
End Try

End Sub
End Class
End Namespace

Next Part à

File Transfer using C# .Net Socket Programming 3/3

Previous part ß

Continued code...

Server Code:

[C#]

using System;

using System.Collections.Generic;

using System.Text;

using System.Net;

using System.Net.Sockets;

using System.IO;

namespace beginSocketServer

{

//FILE TRANSFER USING C#.NET SOCKET PROGRAMMING - SERVER

class Program

{

static void Main(string[] args)

{

try

{

Console.WriteLine("That program can transfer small file. I've test up to 850kb file");

IPEndPoint ipEnd = new IPEndPoint(IPAddress.Any, 5656);

Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);

sock.Bind(ipEnd);

sock.Listen(100);

Socket clientSock = sock.Accept();

byte[] clientData = new byte[1024 * 5000];

string receivedPath = "e:/";

int receivedBytesLen = clientSock.Receive(clientData);

int fileNameLen = BitConverter.ToInt32(clientData, 0);

string fileName = Encoding.ASCII.GetString(clientData, 4, fileNameLen);

Console.WriteLine("Client:{0} connected & File {1} started received.", clientSock.RemoteEndPoint, fileName);

BinaryWriter bWrite = new BinaryWriter(File.Open(receivedPath + fileName, FileMode.Append)); ;

bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen);

Console.WriteLine("File: {0} received & saved at path: {1}", fileName, receivedPath);

bWrite.Close();

clientSock.Close();

Console.ReadLine();

}

catch (Exception ex)

{

Console.WriteLine("File Receiving fail." + ex.Message);

}

}

}

}

[Visual Basic]

Imports System

Imports System.Collections.Generic

Imports System.Text

Imports System.Net

Imports System.Net.Sockets

Imports System.IO

Namespace beginSocketServer

'FILE TRANSFER USING C#.NET SOCKET PROGRAMMING- SERVER

Class Program

Private Shared Sub Main(ByVal args As String())

Try

Console.WriteLine("That program can transfer small file. I've test up to 850kb file")

Dim ipEnd As New IPEndPoint(IPAddress.Any, 5656)

Dim sock As New Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP)

sock.Bind(ipEnd)

sock.Listen(100)

Dim clientSock As Socket = sock.Accept()

Dim clientData As Byte() = New Byte(1024 5000 - 1) {}

Dim receivedPath As String = "e:/"

Dim receivedBytesLen As Integer = clientSock.Receive(clientData)

Dim fileNameLen As Integer = BitConverter.ToInt32(clientData, 0)

Dim fileName As String = Encoding.ASCII.GetString(clientData, 4, fileNameLen)

Console.WriteLine("Client:{0} connected & File {1} started received.", clientSock.RemoteEndPoint, fileName)

Dim bWrite As New BinaryWriter(File.Open(receivedPath + fileName, FileMode.Append))

bWrite.Write(clientData, 4 + fileNameLen, receivedBytesLen - 4 - fileNameLen)

Console.WriteLine("File: {0} received & saved at path: {1}", fileName, receivedPath)

bWrite.Close()

clientSock.Close()

Console.ReadLine()

Catch ex As Exception

Console.WriteLine("File Receiving fail." & ex.Message)

End Try

End Sub

End Class

End Namespace